4x^2+60x-1800=0

Solution for 4x^2+60x-1800=0 equation:

4x^2+60x-1800=0

a = 4; b = 60; c = -1800;
Δ = b2-4ac
Δ = 602-4·4·(-1800)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-180}{2*4}=\frac{-240}{8}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+180}{2*4}=\frac{120}{8}
=15
$